Ответ №1
F'(x)=((x²+x+1)/(x²+1))'=[(x²+x+1)' *(x²+1)-(x²+1)' *(x²+x+1)] / [(x²+1)²]=
=[(2x+1)*(x²+1)-2x*(x²+x+1)] / [(x²+1)²]=[2x³+x²+2x+1-2x³-2x²-2x] / [(x²+1)²]=[-x²+1]/[(x²+1)²]
Ответ №1
F'(x)=((x²+x+1)/(x²+1))'=[(x²+x+1)' *(x²+1)-(x²+1)' *(x²+x+1)] / [(x²+1)²]=
=[(2x+1)*(x²+1)-2x*(x²+x+1)] / [(x²+1)²]=[2x³+x²+2x+1-2x³-2x²-2x] / [(x²+1)²]=[-x²+1]/[(x²+1)²]
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