Ответ №1
A(bc-a²)/a²b+b(ac-b²)b²c+c(ab-c²)/c²a=
=(bc-a²)/(ab+(ac-b²)/bc+(ab-c²)/ca=(bc²-a²c+a²c-ab²+ab²-bc²)/abc=0/abc=0
Ответ №1
A(bc-a²)/a²b+b(ac-b²)b²c+c(ab-c²)/c²a=
=(bc-a²)/(ab+(ac-b²)/bc+(ab-c²)/ca=(bc²-a²c+a²c-ab²+ab²-bc²)/abc=0/abc=0
Знаете ответ?