Ответ №1
2 sinα *cosα = sin2α⇒ sinα*cosα=(sin(2α))/2
sin(π/8)*cos(π/8)= sin (2*π/8)/2= (sin (π/4))/2=√2/4
Ответ №1
2 sinα *cosα = sin2α⇒ sinα*cosα=(sin(2α))/2
sin(π/8)*cos(π/8)= sin (2*π/8)/2= (sin (π/4))/2=√2/4
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