Ответ №1
Y' = 2(x + 2)(x - 10) + (x + 2)^2 = (x + 2)(2(x - 10) + x + 2) = (x + 2)(3x - 18) = 3(x + 2)(x - 6)
Y' = 0, когда x = -2; x = 6
Y (-1) = (-1 + 2)^2 * (-1 - 10) + 156 = 1 * (-11) + 156 = -11 + 156 = 145
Y (6) = (6 + 2)^2 * (6 - 10) + 156 = 64 * (-4) + 156 = -100
Y (20) = (20 + 2)^2 * (20 - 10) + 156 = 484 * 10 + 156 = 4996
Ymin = Y (6) = -100
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