Ответ №1
√2/2 ·sinx -√2/2 ·cosx=1
sinx·cosπ/4 - cosx·sinπ/4 =1
sin(x-π/4) =1
x-π/4=π/2 + 2πk ; k∈Z
x = 3/4 ·π + 2πk ; k∈Z
Ответ №1
√2/2 ·sinx -√2/2 ·cosx=1
sinx·cosπ/4 - cosx·sinπ/4 =1
sin(x-π/4) =1
x-π/4=π/2 + 2πk ; k∈Z
x = 3/4 ·π + 2πk ; k∈Z
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